2013 AMC 12B Problem 1

Attempt Problem 1 of the 2013 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

On a particular January day, the high temperature in Lincoln, Nebraska, was 1616 degrees higher than the low temperature, and the average of the high and low temperatures was 3∘.3^\circ. In degrees, what was the low temperature in Lincoln that day?
−13-13
−8-8
−5-5
−3-3
1111
Answer: C
Concepts:meanlinear equation
Small hint:
The high and low differ by 16,16, so each is 88 away from their average
Big hint:
The low temperature is 88 below the average of 33
Solution:
The high exceeds the low by 16,16, so the low is 88 below the average. Since the average is 3∘,3^\circ, the low temperature is 3−8=−5∘.3 - 8 = -5^\circ. Thus, the correct answer is C.
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