2011 AMC 12A Problem 4

Attempt Problem 4 of the 2011 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

At an elementary school, the students in third grade, fourth grade, and fifth grade run an average of 12,12, 15,15, and 1010 minutes per day, respectively. There are twice as many third graders as fourth graders, and twice as many fourth graders as fifth graders. What is the average number of minutes run per day by these students?
1212
373\dfrac{37}{3}
887\dfrac{88}{7}
1313
1414
Answer: C
Concepts:weighted meanratio and proportion
Small hint:
Let the number of fifth graders be 1,1, so fourth graders is 22 and third graders is 44
Big hint:
The average is 4⋅12+2⋅15+1⋅104+2+1\dfrac{4 \cdot 12 + 2 \cdot 15 + 1 \cdot 10}{4 + 2 + 1}
Solution:
Take the grade sizes in the ratio 4:2:14 : 2 : 1 for third, fourth, and fifth grades. The weighted average is 4⋅12+2⋅15+107=48+30+107=887. \begin{aligned} \dfrac{4\cdot12+2\cdot15+10}{7} \\ = \dfrac{48+30+10}{7} \\ = \dfrac{88}{7}. \end{aligned}
Thus, the correct answer is C.
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