2017 AMC 12B Problem 4

Below is the professionally curated solution for Problem 4 of the 2017 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 12B solutions, or check the answer key.

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Concepts:distance rate and timelinear equation

Difficulty rating: 1270

4.

Samia set off on her bicycle to visit her friend, traveling at an average speed of 1717 kilometers per hour. When she had gone half the distance to her friend's house, a tire went flat, and she walked the rest of the way at 55 kilometers per hour. In all it took her 4444 minutes to reach her friend's house. In kilometers rounded to the nearest tenth, how far did Samia walk?

2.02.0

2.22.2

2.82.8

3.43.4

4.44.4

Solution:

Let 2d2d be the total distance, so she biked dd at 1717 km/h and walked dd at 55 km/h. The total time in hours is d17+d5=4460.\frac{d}{17} + \frac{d}{5} = \frac{44}{60}. Combining the left side gives 22d85=1115,\dfrac{22d}{85} = \dfrac{11}{15}, so d=11158522=176=2.833d = \dfrac{11}{15} \cdot \dfrac{85}{22} = \dfrac{17}{6} = 2.833\ldots She walked about 2.82.8 kilometers.

Thus, the correct answer is C.

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