2017 AMC 12B Problem 5

Below is the professionally curated solution for Problem 5 of the 2017 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 12B solutions, or check the answer key.

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Concepts:median (data)

Difficulty rating: 1130

5.

The data set [6,19,33,33,39,41,41,43,51,57][6, 19, 33, 33, 39, 41, 41, 43, 51, 57] has median Q2=40,Q_2 = 40, first quartile Q1=33,Q_1 = 33, and third quartile Q3=43.Q_3 = 43. An outlier in a data set is a value that is more than 1.51.5 times the interquartile range below the first quartile (Q1)(Q_1) or more than 1.51.5 times the interquartile range above the third quartile (Q3),(Q_3), where the interquartile range is defined as Q3Q1.Q_3 - Q_1. How many outliers does this data set have?

00

11

22

33

44

Solution:

The interquartile range is 4333=10,43 - 33 = 10, so 1.51.5 times it is 15.15. Outliers are values less than 3315=1833 - 15 = 18 or greater than 43+15=58.43 + 15 = 58. Only 66 falls below 18,18, and nothing exceeds 58,58, so there is exactly 11 outlier.

Thus, the correct answer is B.

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