2024 AMC 12A Problem 5

Below is the professionally curated solution for Problem 5 of the 2024 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2024 AMC 12A solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:meanlinear equation

Difficulty rating: 1230

5.

A data set containing 2020 numbers, some of which are 6,6, has mean 45.45. When all the 66s are removed, the data set has mean 66.66. How many 66s were in the original data set?

44

55

66

77

88

Solution:

The full set sums to 2045=900.20\cdot45=900. Removing kk sixes leaves 20k20-k numbers summing to 9006k,900-6k, with mean 66,66, so 9006k=66(20k)=132066k.900-6k=66(20-k)=1320-66k. Then 60k=420,60k=420, giving k=7.k=7. Thus, the correct answer is D.

Problem 5 in Other Years