2010 AMC 12A Problem 9

Attempt Problem 9 of the 2010 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 12A solutions, or check the answer key.

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9.

A solid cube has side length 33 inches. A 22-inch by 22-inch square hole is cut into the center of each face. The edges of each cut are parallel to the edges of the cube, and each hole goes all the way through the cube. What is the volume, in cubic inches, of the remaining solid?
77
88
1010
1212
1515
Answer: A
Concepts:volumeinclusion-exclusioncube geometry
Small hint:
Use inclusion-exclusion for the three rectangular holes
Big hint:
The three 2×2×32\times2\times3 holes overlap in the central 2×2×22\times2\times2 cube
Solution:
Note that all the cut out solids intersect in the middle of the cube.
This region of intersection is a cube with side length 2.2. Then the volume of the cutout region is 3⋅2⋅2⋅3−2⋅23=36−16=20. \begin{align*}3 \cdot 2 \cdot 2 \cdot 3 - 2 \cdot 2^3 &= 36 - 16 \\&= 20.\end{align*}
We have to subtract out the center region twice since it is included in all 33 regions.
The remaining volume is then 33−20=27−20=7. 3^3 - 20 = 27 - 20 = 7.
Thus, A is the correct answer.
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