2010 AMC 12A Problem 1 — Solution | LIVE by Po-Shen Loh

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2010 AMC 12A Problem 1

Attempt Problem 1 of the 2010 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

What is $(20-(2010-201))$ $+(2010-(201-20))?$

$-4020$

$0$

$40$

$401$

$4020$

Answer: C

Concepts:whole number operations order of operations

Difficulty rating: 770

Solution:

Distributing the negative signs gives $\begin{aligned} &(20-2010+201) \\ &\quad {}+(2010-201+20)=40. \end{aligned}$

Thus, C is the correct answer.

Problem 2#2 →

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