2009 AMC 12A Problem 9

Attempt Problem 9 of the 2009 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 12A solutions, or check the answer key.

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9.

Suppose that f(x+3)=3x2+7x+4f(x + 3) = 3x^2 + 7x + 4 and f(x)=ax2+bx+c.f(x) = ax^2 + bx + c. What is a+b+c?a + b + c?

1-1

00

11

22

33

Answer: D
Concepts:functionsubstitution
Difficulty rating: 1350
Solution:

Note that a+b+c=f(1).a + b + c = f(1).

Using f(x+3)=3x2+7x+4f(x + 3) = 3x^2 + 7x + 4 with x=2x = -2 gives f(1)=f(2+3)=3(2)2+7(2)+4=1214+4=2. \begin{aligned} f(1) &= f(-2 + 3) \\ &= 3(-2)^2 + 7(-2) + 4 \\ &= 12 - 14 + 4 = 2. \end{aligned}

Thus, the correct answer is D.

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