2004 AMC 12B Problem 11

Attempt Problem 11 of the 2004 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

All the students in an algebra class took a 100100-point test. Five students scored 100,100, each student scored at least 60,60, and the mean score was 76.76. What is the smallest possible number of students in the class?
1010
1111
1212
1313
1414
Answer: D
Concepts:meanbounding to limit cases
Small hint:
Measure each score as its deviation from the mean 7676
Big hint:
The five 100100s are 120120 points above the mean; each other student is at most 1616 below it
Solution:
Each score of 100100 is 2424 above the mean, so the five contribute 120120 points above 76.76. These must be balanced by points below the mean, and each remaining student is at most 76−60=1676 - 60 = 16 below. So at least 12016=7.5,\dfrac{120}{16} = 7.5, hence 88 more students are needed, for a total of 13.13. Five 100100s and eight 6161s achieve this.
Thus, the correct answer is D.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.