2004 AMC 12A Problem 11

Attempt Problem 11 of the 2004 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

The average value of all the pennies, nickels, dimes, and quarters in Paula’s purse is 2020 cents. If she had one more quarter, the average value would be 2121 cents. How many dimes does she have in her purse?
00
11
22
33
44
Answer: A
Concepts:meanlinear equation
Small hint:
Let nn be the current number of coins and write the total value two ways after adding a quarter
Big hint:
Solve 20n+25=21(n+1)20n + 25 = 21(n + 1) for n,n, then figure out which coins total 20n20n cents
Solution:
If Paula has nn coins, their total value is 20n20n cents. Adding a quarter gives n+1n + 1 coins worth 20n+2520n + 25 cents, which must also equal 21(n+1)21(n + 1) cents.
So 20n+25=21(n+1),20n + 25 = 21(n + 1), giving n=4.n = 4.
Four coins totalling 8080 cents must be three quarters and one nickel, so the number of dimes is 0.0.
Thus, the correct answer is A.
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