1999 AMC 12 Problem 11

Attempt Problem 11 of the 1999 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1999 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

The student lockers at Olympic High are numbered consecutively beginning with locker number 1.1. The plastic digits used to number the lockers cost 22 cents apiece. Thus, it costs 22 cents to label locker number 99 and 44 cents to label locker number 10.10. If it costs $137.94\$137.94 to label all the lockers, how many lockers are there at the school?
20012001
20102010
21002100
27262726
68976897
Answer: A
Concepts:digitscounting integers in a range
Small hint:
Divide the total cost by the cost per digit to get the number of digits
Big hint:
Subtract the digits used by lockers 11-9,9, 1010-99,99, and 100100-999999
Solution:
Labeling costs $137.94$0.02=6897\frac{\$137.94}{\$0.02} = 6897 digits. Lockers 11-99 use 99 digits, lockers 1010-9999 use 2⋅90=1802 \cdot 90 = 180 digits, and lockers 100100-999999 use 3⋅900=27003 \cdot 900 = 2700 digits.
The remaining digits number 6897−2700−180−9=4008,6897 - 2700 - 180 - 9 = 4008, which label 40084=1002\frac{4008}{4} = 1002 four-digit lockers. In all there are 999+1002=2001999 + 1002 = 2001 lockers.
Thus, the correct answer is A.
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