1993 AMC 12 Problem 9

Attempt Problem 9 of the 1993 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

Country AA has c%c\% of the world’s population and owns d%d\% of the world’s wealth. Country BB has e%e\% of the world’s population and f%f\% of its wealth. Assume that the citizens of AA share the wealth of AA equally, and assume that those of BB share the wealth of BB equally. Find the ratio of the wealth of a citizen of AA to the wealth of a citizen of B.B.
cdef\frac{cd}{ef}
cedf\frac{ce}{df}
cfde\frac{cf}{de}
decf\frac{de}{cf}
dfce\frac{df}{ce}
Answer: D
Concepts:ratiosper-capita quantitiescomplex fractions
Small hint:
Per-capita wealth is total wealth divided by population
Big hint:
Form the ratio dcfe\frac{\frac{d}{c}}{\frac{f}{e}}
Solution:
Country AA’s per-capita share is proportional to dc,\frac{d}{c}, while country BB’s is proportional to fe.\frac{f}{e}. Their ratio is dcfe=decf. \frac{\frac{d}{c}}{\frac{f}{e}}=\frac{de}{cf}. Thus the correct answer is D.
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