1993 AMC 12 Problem 27

Attempt Problem 27 of the 1993 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 12 solutions, or check the answer key.

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27.

The sides of ABC\triangle ABC have lengths 6,6, 88 and 10.10. A circle with center PP and radius 11 rolls around the inside of ABC,\triangle ABC, always remaining tangent to at least one side of the triangle. When PP first returns to its original position, through what distance has PP traveled?

1010

1212

1414

1515

1717

Answer: B
Concepts:inner parallel triangleangle bisectorsright triangle
Difficulty rating: 2170
Small Hint:

The center traces a smaller triangle whose sides are parallel to the original sides

Big Hint:

The original 66-88-1010 triangle has inradius 2,2, while the center’s path has inradius 11

Solution:

The center PP remains one unit from the side it touches, so its path is the triangle formed by the three inward parallel lines at distance 1.1. This triangle is similar to ABC.\triangle ABC. The original right triangle has area 2424 and semiperimeter 12,12, hence inradius 2412=2.\frac{24}{12}=2. The path triangle has inradius 21=1,2-1=1, so its linear scale is 12.\frac{1}{2}. Its perimeter, and therefore the distance traveled, is 12(6+8+10)=12. \frac12(6+8+10)=12. Thus the correct answer is B.

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