1970 AMC 12 Problem 27

Attempt Problem 27 of the 1970 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1970 AMC 12 solutions, or check the answer key.

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27.

In a triangle, the area is numerically equal to the perimeter. What is the radius of the inscribed circle?

22

33

44

55

66

Answer: A
Concepts:incircle, incenter, and inradiustriangle areaperimeter
Difficulty rating: 1830
Small Hint:

Express the area in terms of the inradius and semiperimeter

Big Hint:

Use K=rsK=rs and perimeter =2s=2s

Solution:

If rr is the inradius and ss the semiperimeter, the triangle’s area is K=rs.K=rs. Its perimeter is 2s.2s. The given equality yields rs=2s. rs=2s. Since s>0,s\gt0, we obtain r=2.r=2.

Therefore, the correct answer is A.

← Problem 26#26
Full Exam

Problem 27 in Other Years

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