2025 AMC 10A Problem 17

Attempt Problem 17 of the 2025 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2025 AMC 10A solutions, or check the answer key.

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17.

Let NN be the unique positive integer such that dividing 273436273436 by NN leaves a remainder of 16,16, and dividing 272760272760 by NN leaves a remainder of 15.15. What is the tens digit of N?N?

00

11

22

33

44

Answer: E
Concepts:greatest common divisordivisibility
Difficulty rating: 1730
Solution:

Subtract off the remainders. Both 273420=27343616273420 = 273436 - 16 and 272745=27276015272745 = 272760 - 15 are multiples of N,N, so their difference 675675 is too. Now 272745=404675+45,272745 = 404 \cdot 675 + 45, which makes 4545 a multiple of NN as well. The remainder 1616 means N>16,N \gt 16, and the only divisor of 4545 bigger than 1616 is 4545 itself. So N=45,N = 45, and its tens digit is 4.4. Thus, E is the correct answer.

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