2015 AMC 10B Problem 17

Below is the professionally curated solution for Problem 17 of the 2015 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 10B solutions, or check the answer key.

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Concepts:polyhedronpyramidvolume

Difficulty rating: 1420

17.

The centers of the faces of the right rectangular prism shown below are joined to create an octahedron. What is the volume of this octahedron? \t\t

7512 \dfrac{75}{12}

10 10

12 12

102 10\sqrt{2}

15 15

Solution:

The octahedron can be viewed as two congruent pyramids whose shared base is the rhombus through the centers of the four side faces. This rhombus has diagonals 44 and 55, so its area is 1245=10\frac12\cdot4\cdot5=10.

Each pyramid has height 32\frac32, half the prism's height. Thus the total volume is 2131032=10.2\cdot\frac13\cdot10\cdot\frac32=10.

Thus, the correct answer is B.

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