2021 AMC 10B Fall Problem 8

Attempt Problem 8 of the 2021 AMC 10B Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10B Fall solutions, or check the answer key.

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8.

The greatest prime number that is a divisor of 16,38416{,}384 is 22 because 16,384=214.16{,}384 = 2^{14}. What is the sum of the digits of the greatest prime number that is a divisor of 16,383?16{,}383?
3 3
7 7
10 10
16 16
22 22
Answer: C
Concepts:prime factorizationdifference of squares
Small hint:
16383=214−116383=2^{14}-1
Big hint:
Use 214−1=(27−1)(27+1)2^{14}-1=(2^7-1)(2^7+1)
Solution:
We know 16,383=16384−1=214−1=(27−1)(27+1)=127⋅129.\begin{aligned}16,383 &= 16384-1 \\&= 2^{14}-1 \\&= (2^7-1)(2^7+1) \\&= 127\cdot 129.\end{aligned} Since 129=3⋅43,129=3\cdot 43, we get 16383=3⋅43⋅127.16383 = 3\cdot 43\cdot 127. Therefore, 127127 is the largest prime factor, and the sum of its digits is 10.10.
Thus, the answer is C .
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