2016 AMC 10B Problem 8

Below is the professionally curated solution for Problem 8 of the 2016 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10B solutions, or check the answer key.

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Concepts:modular arithmeticChinese Remainder Theorem

Difficulty rating: 1420

8.

What is the tens digit of 201520162017?2015^{2016}-2017?

 0 \ 0

 1 \ 1

 3 \ 3

 5 \ 5

 8 \ 8

Solution:

To find the tens digit, we first need to find the number modulo 100.100. First, we can find 20152016mod100.2015^{2016} \mod 100. We can do this with the Chinese Remainder Theorem by first getting the number mod4\mod 4 and then mod25.\mod 25.

The number 201520160mod252015^{2016} \equiv 0 \mod 25 since it is a multiple of 25.25.

Then, observe that 20152016(1)20162015^{2016} \equiv (-1)^{2016}1mod4. \equiv 1 \mod 4 .

By the Chinese remainder theorem, we can get that our number is congruent to 25mod100.25 \mod 100.

Therefore, 2015201620172015^{2016}-2017 2517mod100\equiv 25 - 17 \mod 1008mod100.\equiv 8 \mod 100 . This means the tens digit is 0.0.

Thus, the correct answer is A .

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