2021 AMC 10B Fall Problem 7

Below is the professionally curated solution for Problem 7 of the 2021 AMC 10B Fall, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10B Fall solutions, or check the answer key.

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Concepts:fractiondivisibilitysystematic listing

Difficulty rating: 1660

7.

Call a fraction ab,\frac{a}{b}, not necessarily in the simplest form, ''special'' if aa and bb are positive integers whose sum is 15.15. How many distinct integers can be written as the sum of two, not necessarily different, special fractions?

 9 \ 9

 10 \ 10

 11 \ 11

 12 \ 12

 13 \ 13

Solution:

A special fraction with denominator bb equals 15bb=15b1\frac{15-b}{b}=\frac{15}{b}-1, where 1b141\le b\le14. We need integer values of 15x+15y2\frac{15}{x}+\frac{15}{y}-2.

Checking the possible denominators by fractional part gives the distinct integer sums 1,2,3,4,6,7,8,13,16,18,28.1,2,3,4,6,7,8,13,16,18,28.

There are 1111 such integers.

Thus, the answer is C .

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