2015 AMC 10A Problem 7

Below is the professionally curated solution for Problem 7 of the 2015 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 10A solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:arithmetic sequence

Difficulty rating: 870

7.

How many terms are in the arithmetic sequence 13,13, 16,16, 19,19, ,\dotsc, 70,70, 73?73?

2020

2121

2424

6060

6161

Solution:

Recall that the nn th term of an arithmetic sequence is a+d(n1),a + d(n - 1), where aa is the first term and dd is the common difference.

For us, a=13a = 13 and d=3.d = 3. Plugging these in, we get that 73=13+3(n1)20=n1n=21.\begin{align*} 73 &= 13 + 3(n - 1) \\ 20&= n - 1 \\ n &= 21. \end{align*} Thus, B is the correct answer.

Problem 7 in Other Years