2021 AMC 10B Fall Problem 14

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14.

Una rolls 66 standard 66-sided dice simultaneously and calculates the product of the 66 numbers obtained. What is the probability that the product is divisible by 4?4?

34 \dfrac34

5764 \dfrac{57}{64}

5964 \dfrac{59}{64}

187192 \dfrac{187}{192}

6364 \dfrac{63}{64}

Answer: C
Concepts:dice (probability)complementary probabilitycasework
Difficulty rating: 1140
Solution:

Count the complement, where the product is not divisible by 4.4. This happens if the product has no factor of 2,2, or exactly one factor of 2.2.

All dice odd has probability (12)6=164.(\frac12)^6=\frac1{64}. Exactly one factor of 22 means exactly one die is 22 or 6,6, and the other five dice are odd. This has probability 626(12)5=464.6\cdot\frac26\cdot\left(\frac12\right)^5=\frac4{64}.

The complement has probability 564,\frac5{64}, so the desired probability is 1564=5964.1-\frac5{64}=\frac{59}{64}.

Thus, the answer is C .

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