2017 AMC 10B Problem 17

Attempt Problem 17 of the 2017 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 10B solutions, or check the answer key.

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17.

Call a positive integer monotonous if it is a one-digit number or its digits, when read from left to right, form either a strictly increasing or a strictly decreasing sequence. For example, 3,3, 23578,23578, and 987620987620 are monotonous, but 88,88, 7434,7434, and 2355723557 are not. How many monotonous positive integers are there?
10241024
15241524
15331533
15361536
20482048
Answer: B
Concepts:subsetsdigitsbijection
Small hint:
Increasing numbers are determined by their digit set
Big hint:
Decreasing numbers may include 00, but the number 00 itself is not positive
Solution:
The strictly increasing positive integers correspond to the nonempty subsets of {1,2,3,4,5,6,7,8,9}\{1,2,3,4,5,6,7,8,9\}, written in increasing order. There are 29−1=5112^9-1=511 of these.
The strictly decreasing positive integers correspond to subsets of {0,1,2,3,4,5,6,7,8,9}\{0,1,2,3,4,5,6,7,8,9\}, written in decreasing order, except for the empty set and {0}\{0\}. There are 210−2=10222^{10}-2=1022 of these.
The one-digit numbers 11 through 99 were counted in both groups, so the total is 511+1022−9=1524511+1022-9=1524. Thus, B is the correct answer.
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