2016 AMC 10B Problem 7

Attempt Problem 7 of the 2016 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

The ratio of the measures of two acute angles is 5:4,5:4, and the complement of one of these two angles is twice as large as the complement of the other. What is the sum of the degree measures of the two angles?
 75 \ 75
 90 \ 90
 135 \ 135
 150 \ 150
 270 \ 270
Answer: C
Concepts:ratio and proportionlinear equation
Small hint:
Let the smaller acute angle be xx
Big hint:
The larger angle has the smaller complement
Solution:
Let the smaller angle be x.x. Then, the larger angle is 54x.\frac 54 x. Note that their sum is 94x.\frac 94 x.
Their complements are then 90−x90-x and 90−54x.90 - \frac 54x. Since 90−x90-x is larger than 90−54x,90-\frac 54 x, we know 90−x=2(90−54x)90−x=180−52xx=60.\begin{aligned}90 -x &= 2\left(90 - \frac 54 x\right) \\90-x&= 180-\frac 52 x\\x&=60.\end{aligned}
Therefore, the sum is 94⋅60=135.\dfrac 94 \cdot 60=135.
Thus, the correct answer is C .
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