2016 AMC 10B Problem 6
Attempt Problem 6 of the 2016 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10B solutions, or check the answer key.
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6.
Laura added two three-digit positive integers. All six digits in these numbers are different. Laura's sum is a three-digit number What is the smallest possible value for the sum of the digits of
Answer: B
Solution:
To minimize the sum of the addends, use the two smallest nonzero hundreds digits, and , and then the four smallest remaining digits, . Placing the smaller digits in the tens places shows that every possible sum is at least . On the other hand, any three-digit number with digit sum less than is at most . Therefore the digit sum of is at least .
The example uses six distinct digits and has digit sum . Thus the smallest possible digit sum is .
Thus, the correct answer is B.
Problem 6 in Other Years
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