2016 AMC 10B Problem 1

Attempt Problem 1 of the 2016 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

What is the value of 2a−1+a−12a\dfrac{2a^{-1}+\frac{a^{-1}}{2}}{a} when a=12?a= \tfrac{1}{2}?
 1 \ 1
 2 \ 2
 52 \ \dfrac{5}{2}
 10 \ 10
 20 \ 20
Answer: D
Concepts:exponentsubstitution
Small hint:
Substitute a=12a=\frac{1}{2} after combining powers of aa
Big hint:
Dividing by aa turns a−1a^{-1} into a−2a^{-2}
Solution:
The expression is equivalent to 2a−2+a−22=2.5(a−1)2.2a^{-2}+\frac{a^{-2}}{2} = 2.5 (a^{-1})^2. Then a−1a^{-1} is equal to 112=2,\dfrac{1}{\frac 12} = 2, so our expression is equal to 2.5⋅22=10.2.5\cdot 2^2 = 10.
Thus, the correct answer is D .
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