2014 AMC 10A Problem 10

Attempt Problem 10 of the 2014 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

Five positive consecutive integers starting with aa have average b.b. What is the average of 55 consecutive integers that start with b?b?
a+3a+3
a+4a+4
a+5a+5
a+6a+6
a+7a+7
Answer: B
Concepts:arithmetic sequencemean
Small hint:
The average of five consecutive integers starting at xx is x+2x+2
Big hint:
Apply that rule first to aa, then to bb
Solution:
Note that the average of 55 consecutive numbers starting with xx is 5x+1+2+3+45=x+2. \dfrac{5x + 1 + 2 + 3 + 4}{5} = x + 2.
This means that the average of 55 consecutive integers starting with aa is a+2,a + 2, which we know is b.b.
Furthermore, the average of 55 consecutive numbers starting with bb is b+2=a+4.b + 2 = a + 4.
Thus, B is the correct answer.
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