2012 AMC 10B Problem 10

Attempt Problem 10 of the 2012 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

How many ordered pairs of positive integers (M,N)(M,N) satisfy the equation M6=6N\frac{M}{6}=\frac{6}{N}
6 6
7 7
8 8
9 9
10 10
Answer: D
Concepts:factor countingprime factorization
Small hint:
Cross-multiply the equation
Big hint:
Count the positive divisors of 3636
Solution:
By cross multiplying, we can see that MN=36.MN = 36. Thus, we can make MM any factor of 3636 and then determine NN from it.
Since 36=22⋅32,36=2^2\cdot 3^2, we have (2+1)(2+1)=9(2+1)(2+1)=9 possible choices for M,M, each of which also determine a unique N.N.
Thus, the correct answer is D .
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