2012 AMC 10A Problem 6

Attempt Problem 6 of the 2012 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 10A solutions, or check the answer key.

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6.

The product of two positive numbers is 9.9. The reciprocal of one of these numbers is 44 times the reciprocal of the other number. What is the sum of the two numbers?

103\dfrac{10}{3}

203\dfrac{20}{3}

77

152\dfrac{15}{2}

88

Answer: D
Concepts:system of equationsrational equation
Difficulty rating: 1070
Solution:

Let the two numbers be xx and yy such that xy=9 and 1x=4y. xy = 9 \text{ and } \dfrac{1}{x} = \dfrac{4}{y}.

We get that y=9x y = \dfrac{9}{x} 1x=4x9. \dfrac{1}{x} = \dfrac{4x}{9}. x=32, x = \dfrac{3}{2}, since xx is positive.

Then y=9÷32=6. y = 9 \div \dfrac{3}{2} = 6.

The desired sum is then 6+32=152. 6 + \dfrac{3}{2} = \dfrac{15}{2}.

Thus, D is the correct answer.

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