2011 AMC 10A Problem 7

Attempt Problem 7 of the 2011 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

Which of the following equations does not have a solution?
(x+7)2=0(x + 7)^2 = 0
∣−3x∣+5=0|-3x| + 5 = 0
−x−2=0\sqrt{-x} - 2 = 0
x−8=0\sqrt{x} - 8 = 0
∣−3x∣−4=0|-3x| - 4 = 0
Answer: B
Concepts:absolute valueradical
Small hint:
Check which equation asks a nonnegative expression to be negative
Big hint:
An absolute value plus 55 cannot equal 00
Solution:
A simplifies to x+7=0 x + 7 = 0 x=−7, x = -7, so it has a solution.
B simplifies to ∣−3x∣=−5, |-3x| = -5, which has no solution since absolute value makes everything positive.
Let us make sure that all the other choices have solutions.
C simplifies to −x=2 \sqrt{-x} = 2 −x=4 -x = 4 x=−4, x = -4, which is fine.
D simplifies to x=8 \sqrt{x} = 8 x=64, x = 64, which works.
Finally, E simplifies to ∣−3x∣=4 |-3x| = 4 −3x=±4 -3x = \pm 4 x=±43, x = \pm \dfrac{4}{3}, which has a solution as well.
Thus, B is the correct answer.
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