2011 AMC 10A Problem 17

Attempt Problem 17 of the 2011 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 10A solutions, or check the answer key.

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17.

In the eight term sequence A,A, B,B, C,C, D,D, E,E, F,F, G,G, H,H, the value of CC is 55 and the sum of any three consecutive terms is 30.30. What is A+H?A+H?

1717

1818

2525

2626

4343

Answer: C
Concepts:recursionpattern recognition
Difficulty rating: 1370
Solution:

From the condition about the sequence, we get that A+B+C=30 A + B + C = 30 B=25A. B = 25 - A. Similarly, we get B+C+D=30 B + C + D = 30 D=A. D = A.

Propagating these values through the sequence and repeating the condition for every consecutive triple, we get that E=25A,F=5,G=A, E = 25 - A, F = 5, G = A, and finally, H=25A.H = 25 - A.

The desired sum is then A+25A=25. A + 25 - A = 25.

Thus, C is the correct answer.

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