2009 AMC 10A Problem 6

Attempt Problem 6 of the 2009 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

A circle of radius 22 is inscribed in a semicircle, as shown. The area inside the semicircle but outside the circle is shaded. What fraction of the semicircle’s area is shaded?
12\dfrac{1}{2}
π6\dfrac{\pi}{6}
2π\dfrac{2}{\pi}
23\dfrac{2}{3}
3π\dfrac{3}{\pi}
Answer: A
Concepts:circle areatangent circles
Small hint:
The circle sits on the diameter and touches the arc, so the semicircle has radius 44
Big hint:
Compare the circle’s area to the semicircle’s area
Solution:
The inscribed circle rests on the diameter and is tangent to the arc, so the semicircle has radius 4.4. Its area is 12π(4)2=8π.\dfrac12 \pi (4)^2 = 8\pi.
The circle’s area is π(2)2=4π,\pi(2)^2 = 4\pi, so the shaded area is 8π−4π=4π.8\pi - 4\pi = 4\pi.
The shaded fraction is 4π8π=12.\dfrac{4\pi}{8\pi} = \dfrac12.
Thus, the correct answer is A.
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