2007 AMC 10B Problem 6

Attempt Problem 6 of the 2007 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

The 20072007 AMC 1010 will be scored by awarding 66 points for each correct response, 00 points for each incorrect response, and 1.51.5 points for each problem left unanswered. After looking over the 2525 problems, Sarah has decided to attempt the first 2222 and leave only the last 33 unanswered. How many of the first 2222 problems must she solve correctly in order to score at least 100100 points?
1313
1414
1515
1616
1717
Answer: D
Concepts:inequalitylinear equation
Small hint:
The unanswered problems still contribute points
Big hint:
Subtract the points from the 33 blanks, then divide the remaining needed points by 66
Solution:
The three blank problems give 3⋅1.5=4.53\cdot 1.5 = 4.5 points, so Sarah needs 100−4.5=95.5100-4.5=95.5 points from the first 22.22.
Since 95.56\frac{95.5}{6} lies between 1515 and 16,16, she must answer at least 1616 correctly, which would give a score of 100.5.100.5.
Thus, the correct answer is D.
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