2007 AMC 10B Problem 20

Attempt Problem 20 of the 2007 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

A set of 2525 square blocks is arranged into a 5×55\times 5 square. How many different combinations of 33 blocks can be selected from that set so that no two are in the same row or column?
100100
125125
600600
23002300
36003600
Answer: C
Concepts:combinationspermutationsarrangements with restrictions
Small hint:
Choose which 33 rows and which 33 columns are used
Big hint:
After picking 33 rows and 33 columns, the blocks correspond to a matching between them
Solution:
Choose 33 of the 55 rows in (53)=10\binom{5}{3}=10 ways and 33 of the 55 columns in (53)=10\binom{5}{3}=10 ways.
The three chosen blocks must occupy distinct rows and columns, so they form a matching between the three rows and three columns, which can be done in 3!=63!=6 ways.
The total is 10⋅10⋅6=600.10\cdot 10\cdot 6=600.
Thus, the correct answer is C.
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