2005 AMC 10B Problem 19

Attempt Problem 19 of the 2005 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

19.

On a certain math exam, 10%10\% of the students got 7070 points, 25%25\% got 8080 points, 20%20\% got 8585 points, 15%15\% got 9090 points, and the rest got 9595 points. What is the difference between the mean and the median score on this exam?
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11
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55
Answer: B
Concepts:meanmedian (data)percentage
Small hint:
The remaining percentage scored 95;95; find it first
Big hint:
For the median, find which score the middle student earned using the cumulative percentages
Solution:
The percentage scoring 9595 is 100−10−25−20−15=30.100 - 10 - 25 - 20 - 15 = 30.
The mean is 0.10(70)+0.25(80)+0.20(85)+0.15(90)+0.30(95)=86. \begin{aligned} &0.10(70) + 0.25(80) \\ &\quad {}+ 0.20(85) + 0.15(90) \\ &\quad {}+ 0.30(95) = 86. \end{aligned}
Since 35%35\% scored below 8585 and 35%35\% scored above 85,85, the middle student scored 85,85, so the median is 85.85.
The difference is 86−85=1.86 - 85 = 1.
Thus, B is the correct answer.
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