2002 AMC 10A Problem 19

Below is the professionally curated solution for Problem 19 of the 2002 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 10A solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:sectorregular polygoncircle area

Difficulty rating: 1600

19.

Spot's doghouse has a regular hexagonal base that measures one yard on each side. He is tethered to a vertex with a two-yard rope. What is the area, in square yards, of the region outside the doghouse that Spot can reach?

23π\dfrac{2}{3}\pi

2π2\pi

52π\dfrac{5}{2}\pi

83π\dfrac{8}{3}\pi

3π3\pi

Solution:

At the tether vertex the hexagon blocks its 120120^\circ interior angle, leaving a 240240^\circ sector of radius 2:2: area 240360π(2)2=8π3.\dfrac{240}{360}\pi(2)^2=\dfrac{8\pi}{3}.

Wrapping around each of the two adjacent vertices, 11 yard of rope remains and sweeps a 6060^\circ sector: 260360π(1)2=π3.2\cdot\dfrac{60}{360}\pi(1)^2=\dfrac{\pi}{3}. The total is 8π3+π3=3π.\dfrac{8\pi}{3}+\dfrac{\pi}{3}=3\pi.

Thus, the correct answer is E.

Problem 19 in Other Years