2006 AMC 10A Problem 19

Attempt Problem 19 of the 2006 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 10A solutions, or check the answer key.

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19.

How many non-similar triangles have angles whose degree measures are distinct positive integers in arithmetic progression?

00

11

5959

8989

178178

Answer: C
Concepts:angle sumarithmetic sequencecounting integers in a range
Difficulty rating: 1630
Small Hint:

If the angles are in arithmetic progression, the middle angle is 60∘60^\circ

Big Hint:

The common difference dd satisfies 1≤d≤591 \le d \le 59

Solution:

Let the angles be n−d,n - d, n,n, n+d.n + d. Their sum is 3n=180,3n = 180, so n=60.n = 60.

The measures are distinct positive integers, so d≥1,d \ge 1, and n−d>0n - d \gt 0 forces d<60.d \lt 60. Thus d∈{1,2,…,59},d \in \{1, 2, \ldots, 59\}, giving 5959 non-similar triangles.

Thus, the correct answer is C.

Problem 18#18
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