2004 AMC 10B Problem 17

Attempt Problem 17 of the 2004 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

17.

The two digits in Jack’s age are the same as the digits in Bill’s age, but in reverse order. In five years Jack will be twice as old as Bill will be then. What is the difference in their current ages?
99
1818
2727
3636
4545
Answer: B
Concepts:agesdigitsDiophantine Equation
Small hint:
Write Jack’s age as 10x+y10x + y and Bill’s as 10y+x10y + x
Big hint:
The condition 10x+y+5=2(10y+x+5)10x + y + 5 = 2(10y + x + 5) reduces to 8x=19y+58x = 19y + 5
Solution:
Let Jack’s age be 10x+y10x + y and Bill’s be 10y+x.10y + x. In five years 10x+y+5=2(10y+x+5),10x + y + 5 = 2(10y + x + 5), which simplifies to 8x=19y+5.8x = 19y + 5.
Since xx and yy are digits, the only solution is y=1,y = 1, x=3.x = 3.
So Jack is 3131 and Bill is 13,13, a difference of 18.18.
Thus, the correct answer is B.
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