2004 AMC 10B Problem 10

Attempt Problem 10 of the 2004 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 10B solutions, or check the answer key.

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10.

A grocer makes a display of cans in which the top row has one can and each lower row has two more cans than the row above it. If the display contains $100$ cans, how many rows does it contain?

$5$

$8$

$9$

$10$

$11$

Answer: D

Concepts:sum of first n odd numbers

Difficulty rating: 1170

Solution:

The rows hold $1, 3, 5, \ldots$ cans, and the sum of the first $n$ odd numbers is $n^2.$

Setting $n^2 = 100$ gives $n = 10.$

Thus, the correct answer is D.

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