2004 AMC 10A Problem 6

Attempt Problem 6 of the 2004 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 10A solutions, or check the answer key.

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6.

Bertha has 66 daughters and no sons. Some of her daughters have 66 daughters, and the rest have none. Bertha has a total of 3030 daughters and granddaughters, and no great-granddaughters. How many of Bertha's daughters and granddaughters have no daughters?

2222

2323

2424

2525

2626

Answer: E
Concepts:basic countinglogical deduction
Difficulty rating: 1170
Solution:

Bertha has 306=2430 - 6 = 24 granddaughters, none of whom have daughters.

These granddaughters belong to 24/6=424 / 6 = 4 of Bertha's daughters. So exactly 44 women have daughters, and the number with no daughters is 304=26. 30 - 4 = 26.

Thus, the correct answer is E.

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