2002 AMC 10A Problem 14

Attempt Problem 14 of the 2002 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

Both roots of the quadratic equation x2−63x+k=0x^2-63x+k=0 are prime numbers. The number of possible values of kk is
00
11
22
44
more than four
Answer: B
Concepts:Vieta’s Formulasprimeparity
Small hint:
The roots sum to 6363 and multiply to kk
Big hint:
An odd sum of two primes forces one of them to be 22
Solution:
If the roots are primes pp and q,q, then p+q=63p+q=63 and pq=k.pq=k. Because 6363 is odd, one prime must be 2,2, making the other 61,61, which is prime.
So k=2⋅61=122k=2\cdot 61=122 is the only possible value.
Thus, the correct answer is B.
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