2001 AMC 10 Problem 7

Attempt Problem 7 of the 2001 AMC 10 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 10 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

When the decimal point of a certain positive decimal number is moved four places to the right, the new number is four times the reciprocal of the original number. What is the original number?
0.00020.0002
0.0020.002
0.020.02
0.20.2
22
Answer: C
Concepts:place valuedecimalalgebraic manipulation
Small hint:
Moving the decimal point four places right multiplies by 1000010000
Big hint:
So 10000x=4x,10000x=\dfrac{4}{x}, giving x2=410000x^2=\dfrac{4}{10000}
Solution:
Moving the decimal four places right multiplies xx by 10000.10000. So 10000x=4⋅1x,10000x=4\cdot\dfrac1x, giving x2=410000.x^2=\dfrac{4}{10000}.
Since x>0,x\gt0, x=2100=0.02.x=\dfrac{2}{100}=0.02.
Thus, the correct answer is C.
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