Question

The diagram shows twenty congruent circles arranged in three rows and enclosed in a rectangle. The circles are tangent to one another and to the sides of the rectangle as shown in the diagram. The ratio of the longer dimension of the rectangle to the shorter dimension can be written as $\frac{1}{2}\left(\sqrt{p} - q\right),$ where $p$ and $q$ are positive integers. Find $p + q.$

Answer

Answer: 154

Concepts:tangent circles equilateral triangle rationalizing denominator

Difficulty rating: 2020

Solution:

Let $r$ be the common radius. The longer side holds a row of seven circles, so it equals $14r.$ The centers of three mutually tangent circles in adjacent rows form an equilateral triangle with side $2r,$ whose height is $r\sqrt{3},$ so the two gaps between rows of centers contribute $2r\sqrt{3},$ and the shorter side is $r + 2r\sqrt{3} + r = 2r + 2r\sqrt{3}.$

The ratio is $\begin{aligned} \frac{14r}{2r\left(1 + \sqrt{3}\right)} &= \frac{7}{1 + \sqrt{3}} \\ &= \frac{7\left(\sqrt{3} - 1\right)}{2} \\ &= \frac{1}{2}\left(\sqrt{147} - 7\right), \end{aligned}$ so $p = 147,$ $q = 7,$ and $p + q = 154.$

2002 AIME I Problem 2

Answer: 154

Difficulty rating: 2020

Solution:

Problem 2 in Other Years