1999 AIME Problem 2

Below is the professionally curated solution for Problem 2 of the 1999 AIME, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1999 AIME solutions, or check the answer key.

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Concepts:parallelogrammidpointslopesymmetry

Difficulty rating: 1790

2.

Consider the parallelogram with vertices (10,45),(10, 45), (10,114),(10, 114), (28,153),(28, 153), and (28,84).(28, 84). A line through the origin cuts this figure into two congruent polygons. The slope of the line is mn,\frac{m}{n}, where mm and nn are relatively prime positive integers. Find m+n.m + n.

Solution:

A parallelogram is symmetric under the 180180^\circ rotation about its center, so any line through the center cuts it into two pieces that are swapped by that rotation, hence congruent. The center is the midpoint of a diagonal: (10+282,45+1532)=(19,99).\left(\frac{10 + 28}{2}, \frac{45 + 153}{2}\right) = (19, 99).

The line through the origin and (19,99)(19, 99) has slope 9919,\frac{99}{19}, and gcd(99,19)=1,\gcd(99, 19) = 1, so m+n=99+19=118.m + n = 99 + 19 = 118.

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