2025 AMC 8 第 14 题

先试着解答 2025 AMC 8 第 14 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2025 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

14.

一个数 NN 被插入列表 22、66、77、77、2828 中。现在平均数是中位数的两倍。NN 是多少?
A number NN is inserted into the list 2,2, 6,6, 7,7, 7,7, 28.28. The mean is now twice as great as the median. What is N?N?
77
1414
2020
2828
3434
答案:E
知识点:平均数中位数(数据)
小提示:
因为每个选项都至少为 77,中位数保持不变
Since every choice is at least 7,7, the median stays fixed
大提示:
令总和等于 66 乘以中位数的两倍
Make the total sum equal to 66 times twice the median
视频讲解:
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文字解答:
插入 NN 后共有 66 个数。个数为偶数,所以中位数是中间两个数的平均。
所有选项都至少为 77,所以插入后中间两个数仍是 77 和 77。方便的是,无论选哪个选项,中位数都是 77。
平均数是中位数的两倍,即 2×7=142 \times 7 = 14。
要让 66 个数的平均数为 1414,总和必须为 6×14=846 \times 14 = 84。
原来 55 个数的和为 2+6+7+7+28=50, 2 + 6 + 7 + 7 + 28 = 50\text{,}所以答案是 84−50=3484 - 50 = 34,选 E。
After inserting NN into the list, there will be 66 total numbers. That is even, so the median will be the average of the middle two numbers.
All of the answer choices are at least 7,7, so when they are inserted into the list, the middle two numbers will be 77 and 7.7. It is convenient that the median will always be 7,7, no matter which answer choice is picked.
The mean becomes twice the median, which is 2×7=14.2 \times 7 = 14.
To have a total of 66 numbers with mean 14,14, their sum must become 6×14=84.6 \times 14 = 84.
The sum of the original 55 numbers is 2+6+7+7+28=50, 2 + 6 + 7 + 7 + 28 = 50, so the answer is 84−50=34,84 - 50 = 34, which is choice E.
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