2025 AMC 8 第 12 题

先试着解答 2025 AMC 8 第 12 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2025 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

12.

下图区域由 2424 个边长为 11 厘米的正方形组成。能放入该区域内部、可以接触边界的最大圆的面积是多少平方厘米?
The region shown below consists of 2424 squares, each with side length 11 centimeter. What is the area, in square centimeters, of the largest circle that can fit inside the region, possibly touching the boundaries?
3π3\pi
4π4\pi
5π5\pi
6π6\pi
8π8\pi
答案:C
知识点:圆面积勾股定理最优化
小提示:
最大圆的圆心在该区域中心
The largest circle is centered at the center of the region
大提示:
求中心到最近内凹角点的距离
Find the distance from the center to the nearest concave corners
视频讲解:
解答视频缩略图
Play video

Click to load, then click again to play

文字解答:
离区域中心最近的边界角点,是图中位于这个圆上的 88 个点:
由勾股定理,每个点到中心的距离为 12+22=5。 \sqrt{1^2 + 2^2} = \sqrt{5}\text{。}所以圆面积为 π(5)2=5π, \pi (\sqrt{5})^2 = 5\pi\text{,}选 C。
The corners of the region which are closest to the center are the 88 points which lie on this circle:
By the Pythagorean Theorem, each of these points has this distance from the center: 12+22=5. \sqrt{1^2 + 2^2} = \sqrt{5}. The area of the circle is then π(5)2=5π, \pi (\sqrt{5})^2 = 5\pi, which is choice C.
LIVE by Po-Shen Loh
LIVE项目

LIVE直播课程

Self-Paced录播课程

启明星Star计划

奖学金项目

关于我们

罗博深是谁?

邮件联系

订阅英文简报

加入我们

申请明星导师

For a more Thought Full world.

© 2026 Expii, Inc.