2019 AMC 8 第 13 题

先试着解答 2019 AMC 8 第 13 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2019 AMC 8 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

13.

回文数是从左到右读和从右到左读数值相同的数。(例如一万二千三百二十一是回文数。)设 NN 是最小的三位整数,它不是回文数,但可以表示成三个不同的两位回文数之和。NN 的数字和是多少?

A palindrome is a number that has the same value when read from left to right or from right to left. (For example, 12321 is a palindrome.) Let NN be the least three-digit integer which is not a palindrome but which is the sum of three distinct two-digit palindromes. What is the sum of the digits of N?N?

22

33

44

55

66

答案:A
知识点:回文数整除性
难度评级:1140
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文字解答:

22 位回文数的十位和个位相同,所以都是 1111 的倍数。

如果一个 33 位数是 33 个不同的 22 位回文数之和,那么它也必须是 1111 的倍数。

最小的 331111 的倍数且不是回文数的是 110110。它可以写成 11+22+7711 + 22 + 77

因此 N=110N = 110,数字和为 1+1+0=21 + 1 + 0 = 2

正确答案是 A

Note that 22-digit palindromes have the tens and units digits the same. This means that they are all multiples of 11.11.

If a 33-digit number is the sum of 33 22-digit palindromes, then it itself must also be a multiple of 11.11.

The smallest 33-digit multiple of 1111 that is not a palindrome is 110.110. This can be achieved by adding 11+22+77.11 + 22 + 77.

Therefore, N=110.N = 110. The sum of its digits is 1+1+0=2.1 + 1 + 0 = 2.

Thus, the correct answer is A.

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