2017 AMC 8 第 13 题

先试着解答 2017 AMC 8 第 13 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2017 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

13.

彼得、艾玛和凯勒互相下棋。彼得赢了 44 局,输了 22 局。艾玛赢了 33 局,输了 33 局。如果凯勒输了 33 局,他赢了多少局?
Peter, Emma, and Kyler played chess with each other. Peter won 44 games and lost 22 games. Emma won 33 games and lost 33 games. If Kyler lost 33 games, how many games did he win?
00
11
22
33
44
答案:B
知识点:逻辑推理
小提示:
每一场胜利都对应另一个人的一场失败
Every recorded win contributes one recorded loss to another player.
大提示:
比较三人总胜场数和总负场数
Compare total wins and total losses across all three players.
视频讲解:
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文字解答:
把三个人的记录合在一起,每一场胜利都对应一场失败;和棋若有,则对胜负总数都没有贡献。总负场数为 2+3+3=82+3+3=8,所以凯勒赢了 8−4−3=18-4-3=1 局。
所以正确答案是 B。
Across all players, every win is matched by one loss; drawn games, if any, contribute neither. The number of losses is 2+3+3=8,2+3+3=8, so the number of games Kyler won is 8−4−3=1.8-4-3=1.
Thus, B is the correct answer.
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