Question

Peter、Emma 和 Kyler 互相下棋。Peter 赢了四局，输了二局。Emma 赢了三局，输了三局。如果 Kyler 输了三局，他赢了多少局？

Peter, Emma, and Kyler played chess with each other. Peter won 4 games and lost 2 games. Emma won 3 games and lost 3 games. If Kyler lost 3 games, how many games did he win?

$0$

$1$

$2$

$3$

$4$

答案：B

知识点：逻辑推理

难度评级：1020

视频讲解：

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文字解答：

因为没有平局，总胜场数必须等于总负场数。总负场数为 $2+3+3=8$ ，所以 Kyler 赢了 $8-4-3=1$ 局。

所以正确答案是 B。

Across all players, every win is matched by one loss; drawn games, if any, contribute neither. The number of losses is $2+3+3=8,$ so the number of games Kyler won is $8-4-3=1.$

Thus, B is the correct answer.

2017 AMC 8 第 13 题

答案：B

难度评级：1020

视频讲解：

文字解答：

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