2015 AMC 8 Problem 4

Below is the video solution and professionally curated solution for Problem 4 of the 2015 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 8 solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:permutationsmultiplication principle

Difficulty rating: 770

4.

The Centerville Middle School chess team consists of two boys and three girls. A photographer wants to take a picture of the team to appear in the local newspaper. She decides to have them sit in a row with a boy at each end and the three girls in the middle. How many such arrangements are possible?

2 2

4 4

5 5

6 6

12 12

Video solution:
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Written solution:

There are 2!=22! = 2 ways to place the two boys at the two ends. There are 3!=63! = 6 ways to arrange the three girls in the middle seats.

Thus the total number of arrangements is 26=122\cdot6=12.

Thus, E is the correct answer.

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