2015 AMC 8 第 15 题

先试着解答 2015 AMC 8 第 15 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2015 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

15.

在欧拉中学,198198 名学生对学校公投中的两个议题进行了投票,结果如下:149149 人支持第一个议题,119119 人支持第二个议题。如果正好有 2929 名学生两个议题都反对,那么有多少名学生两个议题都支持?
At Euler Middle School, 198198 students voted on two issues in a school referendum with the following results. 149149 voted in favor of the first issue and 119119 voted in favor of the second issue. If there were exactly 2929 students who voted against both issues, how many students voted in favor of both issues?
4949
7070
7979
9999
149149
答案:D
知识点:容斥原理
小提示:
先求有多少学生至少支持一个议题
First find how many students voted for at least one issue.
大提示:
对两个支持人数使用容斥原理
Use inclusion-exclusion on the two yes-vote counts.
视频讲解:
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文字解答:
因为 2929 名学生两个议题都反对,所以 198−29=169198-29 = 169 名学生至少支持一个议题。
已知 149149 人支持第一个议题,119119 人支持第二个议题,且 169169 人至少支持一个议题。由容斥原理,两个都支持的人数为 149+119−169=99。149+119-169 = 99\text{。}
所以正确答案是 D。
Since 2929 students voted against both, we know that 198−29=169198-29 = 169 people voted for at least one.
As we know that 149149 students voted for the first issue, and 119119 students voted for the second issue, and 169169 students that voted for at least one issue, we conclude that the number of students that voted for both is 149+119−169=99.149+119-169 = 99.
Thus, the correct answer is D .
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