2013 AMC 8 第 9 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

9.

绿巨人浩克每次跳跃的距离都能比上一次翻倍。如果第一次跳 11 米,第二次跳 22 米,第三次跳 44 米,依此类推,那么他第一次能跳超过 11 千米是在第几跳?

The Incredible Hulk can double the distance he jumps with each succeeding jump. If his first jump is 11 meter, the second jump is 22 meters, the third jump is 44 meters, and so on, then on which jump will he first be able to jump more than 11 kilometer?

99

99th

1010

1010th

1111

1111th

1212

1212th

1313

1313th

答案:C
知识点:2的幂等比数列
难度评级:960
小提示:

nn 跳的长度是 2n12^{n-1}

The nnth jump has length 2n12^{n-1}.

大提示:

22 的幂与 10001000 比较

Compare powers of 22 with 10001000.

视频讲解:
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文字解答:

nn 跳时,浩克跳 2n12^{n-1} 米。需要找最小的 nn,使 2n1>10002^{n-1}>1000

因为 29=5122^9=512,而 210=10242^{10}=1024,所以第一次超过 10001000 米时 n1=10n-1=10,即 n=11n=11

所以正确答案是 C

On the nnth jump, the Hulk jumps 2n12^{n-1} meters. We need the smallest nn for which 2n1>10002^{n-1}>1000.

Since 29=5122^9=512 and 210=10242^{10}=1024, the first jump longer than 10001000 meters has n1=10n-1=10, so n=11n=11.

Thus, C is the correct answer.

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